Which conclusion follows deductively from the assumption that n is divisible by 6?
If n is divisible by 6, n = 6k = 3(2k) for some integer k. Hence n is divisible by 3.
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If n is divisible by 6, n = 6k = 3(2k) for some integer k. Hence n is divisible by 3.
Multiply by (3 + √5)/(3 + √5). The denominator is 9 - 5 = 4, so the expression becomes 4(3 + √5)/4 = 3 + √5.
Let u = x². Then u² - 3u + 1 = 0 has two positive roots. Each positive value of u gives two real values x = ±√u, so there are four real solutions.
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Correct answer: n is divisible by 3
If n is divisible by 6, n = 6k = 3(2k) for some integer k. Hence n is divisible by 3.
Correct answer: 3 + √5
Multiply by (3 + √5)/(3 + √5). The denominator is 9 - 5 = 4, so the expression becomes 4(3 + √5)/4 = 3 + √5.
Correct answer: 4
Let u = x². Then u² - 3u + 1 = 0 has two positive roots. Each positive value of u gives two real values x = ±√u, so there are four real solutions.
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OCR · Mathematics B (MEI) · A Level · Mathematics · H640
Version 3, October 2025, current checked 2026-08-27
Source checked: 2026-08-27. The current official specification controls assessment requirements and option choices.
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